Immunoglobulin G (IgG) cleavage: A specific protease (such as papain) splits an IgG molecule into which defined fragments?
-
AAn antigen-binding site and two constant regions
-
BTwo heavy chain–light chain dimers
-
CAn inactive mixture of oligopeptides
-
DTwo Fab fragments and one Fc fragment
-
EOne F(ab')2 fragment only
Answer
Correct Answer: Two Fab fragments and one Fc fragment
Explanation
Introduction / Context: IgG structure determines how antibodies bind antigen and recruit effector functions. Proteolytic cleavage experiments (papain versus pepsin) are classic tools to map domains and understand function.
Given Data / Assumptions:
- Protease referenced is the classic one used for IgG domain mapping.
- We consider intact IgG with two antigen-binding arms and one constant Fc region.
Concept / Approach: Papain cleaves IgG above the hinge, yielding two monovalent Fab fragments (each with one antigen-binding site) and one Fc fragment (crystallizable fragment mediating effector functions like complement and Fc receptor binding). In contrast, pepsin cuts below the hinge, producing F(ab')2.
Step-by-Step Solution: Recall papain action → cleavage above hinge. Products → Fab + Fab + Fc. Choose the option explicitly naming these three fragments. Confirm that other options describe different outcomes (e.g., pepsin makes F(ab')2).
Verification / Alternative check: Fab retains antigen-binding without effector function; Fc retains constant-region functions without antigen binding.
Why Other Options Are Wrong: Heavy-light dimers not standard nomenclature; random oligopeptides imply nonspecific digestion; F(ab')2 is pepsin product, not papain.
Common Pitfalls: Confusing papain with pepsin; mixing up Fab (monovalent) versus F(ab')2 (bivalent).
Final Answer: Two Fab fragments and one Fc fragment.