Difficulty: Easy
Correct Answer: Two Fab fragments and one Fc fragment
Explanation:
Introduction / Context:
Understanding how antibodies are enzymatically cleaved is foundational in immunology and biotechnology. The classic papain digestion of immunoglobulin G (IgG) produces well-defined fragments that retain specific biological properties used in diagnostics, structural studies, and therapeutics.
Given Data / Assumptions:
Concept / Approach:
Papain cleaves IgG above the hinge region. This releases two identical antigen-binding fragments (Fab) and a single crystallizable fragment (Fc). Each Fab contains one light chain and the corresponding variable and constant domains of a heavy chain, preserving monovalent antigen binding. The Fc fragment contains the effector-mediating CH2–CH3 domains of both heavy chains but lacks antigen-binding sites.
Step-by-Step Solution:
Recognize papain cleavage site: above the hinge region.Predict products: two Fab (each with one antigen-binding site) + one Fc (effector region).Match to options: two Fab fragments and one Fc fragment.
Verification / Alternative check:
Contrast with pepsin cleavage (below the hinge) that yields one F(ab')2 fragment plus degraded Fc pieces. This difference confirms the papain-specific pattern.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing papain with pepsin results; forgetting that Fab is monovalent whereas F(ab')2 is divalent.
Final Answer:
Two Fab fragments and one Fc fragment.
Discussion & Comments