- Let the initial quantity of honey in the jar be x grams.
- In each operation, 20% of honey is removed and replaced with sugar solution.
- This means 80% of honey remains after each operation.
- The operation is repeated 4 times.
- So, remaining honey after 4 operations = x × (0.8)4
It is given that the final quantity of honey left is 512 grams:
x × (0.8)4 = 512
x × 0.4096 = 512
x = 512 / 0.4096
x = 1250
Initial amount of honey in the jar = 1250 grams
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