- Total quantity of mixture = 48 liters
- Initial ratio of milk : water = 5 : 3
- Let’s find the initial quantity of milk and water:
- Milk = (5 / (5 + 3)) × 48 = (5 / 8) × 48 = 30 liters
- Water = 48 - 30 = 18 liters
- Let x liters of water be added
- New quantity of water = 18 + x
- Milk remains unchanged = 30 liters
- New ratio of milk : water = 3 : 5
So we can write the equation as:
30 / (18 + x) = 3 / 5
Cross-multiply:
30 × 5 = 3 × (18 + x)
150 = 54 + 3x
3x = 96
x = 32
Water to be added = 32 liters
Answer: 32 liters
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