4 kg of a metal contains 1/5 copper and rest in Zinc. Another 5 kg of metal contains 1/6 copper and rest in Zinc.The ratio of Copper and Zinc into the mixture of these two metals:

We are given two alloys:

• Alloy A: 4 kg with 1/5 copper and the rest zinc
• Alloy B: 5 kg with 1/6 copper and the rest zinc

First, calculate the amount of copper and zinc in each alloy:

• Alloy A:
• Copper = (1/5) × 4 = 0.8 kg
• Zinc = 4 - 0.8 = 3.2 kg
• Alloy B:
• Copper = (1/6) × 5 = 0.833 kg (or 5/6 kg)
• Zinc = 5 - 0.833 = 4.167 kg (or 25/6 kg - 5/6 kg = 20/6 kg)

Now add copper and zinc from both alloys:

• Total Copper = 0.8 + 0.833 = 1.633 kg (or 49/30 kg)
• Total Zinc = 3.2 + 4.167 = 7.367 kg (or 221/30 kg)

Now find the ratio of copper to zinc:

Copper : Zinc = (49/30) : (221/30)
            = 49 : 221

Answer: 49 : 221