Ages — two-person average with known difference: The average of the present ages of Sachin and Saurabh is 36 years (sum 72). If Sachin is 8 years older than Saurabh, find Saurabh’s present age.

Difficulty: Easy

Correct Answer: 32 yr

Explanation:


Introduction / Context:
Given a two-person average and their difference, we can split the total to find individual ages neatly.


Given Data / Assumptions:

  • (Sachin + Saurabh)/2 = 36 ⇒ sum = 72.
  • Sachin − Saurabh = 8.


Concept / Approach:
Let Saurabh = x and Sachin = x + 8. Then x + (x + 8) = 72 ⇒ solve for x.


Step-by-Step Solution:

2x + 8 = 72 ⇒ 2x = 64 ⇒ x = 32.Hence Saurabh = 32; Sachin = 40.


Verification / Alternative check:

Average = (32 + 40)/2 = 36 ✓ and difference = 8 ✓


Why Other Options Are Wrong:

  • 30 and 34 do not match both constraints simultaneously. 40 is Sachin’s age, not Saurabh’s.


Common Pitfalls:

  • Assigning the 8-year difference to the wrong person.


Final Answer:
32 yr

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