Ages (marriage reference and fractional multiple): Radha married 6 years ago. Today her age is 1.25 times her age at marriage. Her son's age is one-tenth of her present age. Find the son's age.
Verbal Reasoning
Problems on Ages
Difficulty: Easy
Choose an option
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A1 years
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B2 years
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C3 years
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D4 years
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E5 years
Answer
Correct Answer: 3 years
Explanation
Introduction / Context:Here a fractional multiplier ties present age to a past age (at marriage), followed by a simple fraction for the child's age.
Given Data / Assumptions:
- Let marriage age be x years.
- Present age = 1.25 * x = (5/4) * x.
- Also, present age = x + 6 (since marriage was 6 years ago).
- Son's age = (1/10) * present age.
Concept / Approach:Equate the two expressions for present age to find x, then compute present age and take one-tenth for the son.
Step-by-Step Solution:
1) x + 6 = (5/4) * x. 2) Multiply both sides by 4: 4x + 24 = 5x → x = 24. 3) Present age = x + 6 = 30. 4) Son's age = (1/10) * 30 = 3 years.Verification / Alternative check:Check multiplier: (5/4) * 24 = 30, matching the present age used to compute the son's age.
Why Other Options Are Wrong:They correspond to incorrect algebra (e.g., treating 1.25x as x + 1.25).
Common Pitfalls:Forgetting that “married 6 years ago” means present age exceeds marriage age by exactly 6 years, not 6%.
Final Answer:3 years