Silica (SiO2) polymorphs vs. temperature: which crystalline form of silica is thermodynamically stable between 1470°C and its melting point near 1713°C?
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ACristobalite
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BTridymite
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CQuartz
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DNone of these
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EGlassy silica
Answer
Correct Answer: Cristobalite
Explanation
Introduction:Silica exhibits temperature-dependent polymorphism. Correctly identifying the stable phase at high temperatures is important for choosing silica bricks and predicting dimensional changes and thermal-shock behavior in furnaces.
Given Data / Assumptions:
- Temperature range: 1470°C up to the melting point (~1713°C).
- Common polymorphs: quartz (low/high), tridymite, cristobalite.
- We are concerned with equilibrium stability domains, not metastable persistence.
Concept / Approach:Equilibrium phase relationships for SiO2 indicate that quartz is low-temperature, tridymite is intermediate (~870–1470°C), and cristobalite is the high-temperature phase stable from ~1470°C to melting. Bricks and linings must account for the volume changes associated with these transformations.
Step-by-Step Solution:Identify the upper-temperature stable polymorph: cristobalite.Confirm boundaries: tridymite stabilizes below ~1470°C; quartz at still lower temperatures.Therefore, for 1470–1713°C, cristobalite is the correct phase.
Verification / Alternative check:Phase diagrams and refractory textbooks list cristobalite as the stable phase approaching silica’s melting point.
Why Other Options Are Wrong:
- Tridymite: stable at intermediate temperatures below ~1470°C.
- Quartz: low-temperature region; transforms before reaching 1470°C.
- “None of these” and glassy silica: do not represent the equilibrium high-T crystalline silica.
Common Pitfalls:Confusing metastable persistence (e.g., retained tridymite) with true equilibrium stability, and overlooking large volume changes during phase transitions.
Final Answer:Cristobalite