Difficulty: Easy
Correct Answer: astable
Explanation:
Introduction / Context:
Identifying the physical RC network around a 555 quickly tells you its operating mode. Two resistors and one capacitor in the standard arrangement indicate the oscillator setup.
Given Data / Assumptions:
Concept / Approach:
In the astable 555, the capacitor charges through RA + RB and discharges through RB only. That requires two resistors. In monostable, only one resistor and one capacitor set the single shot pulse width.
Step-by-Step Solution:
1) Observe two resistors plus one capacitor: classic astable network.2) Charging path: Vcc → RA → RB → C.3) Discharging path: C → RB → discharge transistor → ground.4) Result is free running oscillation with period T = 0.693 * (RA + 2 * RB) * C and duty cycle set by RA and RB.
Verification / Alternative check:
Monostable uses single R and C and needs an external trigger; Schmitt trigger references input conditioning, not standard 555 timing network.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming any two resistor network is monostable; forgetting the discharge path through RB only.
Final Answer:
astable
Discussion & Comments