Difficulty: Easy
Correct Answer: 13
Explanation:
Introduction / Context:
This problem checks understanding of pulse extension in a retriggerable one shot, such as the 74123 or a retriggerable 555 configuration. Retriggering during an active pulse restarts the timing interval.
Given Data / Assumptions:
Concept / Approach:
In a retriggerable one shot, a new trigger during the active output restarts the internal timing, effectively extending the pulse. The final width equals time from first trigger until the last retrigger plus one full T after that retrigger.
Step-by-Step Solution:
1) First trigger starts a 10 ms pulse at t = 0.2) At t = 3 ms, a second trigger arrives while output is still high.3) The timing interval restarts at t = 3 ms, adding another 10 ms from that instant.4) Total pulse width = 3 ms + 10 ms = 13 ms.
Verification / Alternative check:
General rule: With multiple in window triggers, output duration equals time from first trigger to last trigger plus T. Here there are two triggers, last at 3 ms, so 3 + 10 = 13 ms.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing retriggerable with nonretriggerable; assuming the second trigger only adds the unused remainder.
Final Answer:
13
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