Difficulty: Easy
Correct Answer: True
Explanation:
Introduction / Context:
In AC fields, dielectric materials exhibit frequency-dependent behavior often described by complex quantities: complex permittivity ε* and complex polarizability α*. The real part stores energy; the imaginary part accounts for dissipative loss (heat generation).
Given Data / Assumptions:
Concept / Approach:
The power loss density in a dielectric can be related to the out-of-phase component of polarization relative to the electric field. That out-of-phase component is captured by the imaginary part of α* or equivalently by ε″, the imaginary part of the complex permittivity ε* = ε′ − j ε″. Therefore, α″ directly represents energy dissipation associated with polarization mechanisms.
Step-by-Step Solution:
Express complex polarization: P = N α* E for N polarizable units per volume.Decompose α* into real and imaginary parts: α* = α′ − j α″.Recognize that the quadrature (loss) component contributes to average power absorbed during a cycle.Hence, the imaginary part α″ represents dielectric loss due to polarization lag.
Verification / Alternative check:
Loss tangent tan δ = ε″ / ε′ relates the imaginary and real parts of permittivity; calorimetric or bridge measurements confirm that ε″ and α″ correlate with heating in dielectrics.
Why Other Options Are Wrong:
Limiting validity to “very low frequency” or “only at resonance” is incorrect—loss can exist over broad bands, peaking near relaxation or resonance. Conductors involve additional ohmic loss but the statement concerns dielectrics.
Common Pitfalls:
Confusing dielectric loss with conduction loss; both can coexist but are distinct mechanisms.
Final Answer:
True
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