Question 1

Five policemen are standing in a row facing south. Shekhar is to the immediate right of Dhanush. Bala is between Basha and Dhanush. David is at the extreme right end of the row. Who is standing in the middle of the row?

Accepted Answer

According to question, We can draw a figure , in which Shekhar is to the immediate right of Dhanush. Bala is between Basha and Dhanush. David is at the extreme right end of the row. As shown in figure , Dhanush is standing in the middle. Sitting arrangement :-

Question 2

Six of my colleagues are sitting on the first row in this group photograph. Krishna is to the left of Kumar and to the right of Samy. Vaani is in between Sheela and Kumar. Where is Saroj sitting?

Accepted Answer

Krishna is to the right of Samy. There is no person between Samy and Krishna. There is no person between Vaani and Sheela. So, Saroj is sitting to the left of Samy.

Question 3

Seven persons A, B, C, D, E, F and G are standing in a straight line. D is to the right of G. C is between A and B. E is between F and D. There are three persons between G and B. Who is on the extreme left?

Accepted Answer

According to question, We can draw a figure , in which D is to the right of G. C is between A and B. E is between F and D. There are three persons between G and B . As shown in figure , G is on the extreme left . Standing arrangement :-

Question 4

Six girls A, B, C, D, E, F are sitting on the ground. A and B belong to Ruby House, while the rest belong to Emerald House. D and F are tall, while others are short. C and D are wearing glasses while others are not wearing. Which girl of Emerald Hou…

Accepted Answer

Draw a figure on the basis of above given question ,A and B belong to Ruby House, while the rest belong to Emerald House. D and F are tall, while others are short. C and D are wearing glasses while others are not wearing. D is from Emerald House. She is tall. She wears glasses. sitting sequence :-

Question 5

Five friends are sitting in a row facing South. Here Mohan is between Balu and Raju and Raju is to the immediate right of Praveen and Amith is to the right of Balu. Who is in extreme right end?

Accepted Answer

According to question, We can draw a figure , in which Mohan is between Balu and Raju and Raju is to the immediate right of Praveen and Amith is to the right of Balu. As shown in figure , Amith is in extreme right end . Sitting arrangement :-

Question 6

Five students are standing one behind the other in the playground facing the instructor. Malini is behind Anjana, but in front of Gayathri. Meena is in front of Shena, but behind Gayathri. What is the position of Meena?

Accepted Answer

According to question,Malini is behind Anjana, but in front of Gayathri. Meena is in front of Shena, but behind Gayathri. It is clear that , Meena is second from the last. Standing arrangement :-

Question 7

In a row of students, if John, who is 16th from the left, and Johnson, who is 8th from the right, interchange their positions, John becomes 33rd from left. How many students are there in the row?

Accepted Answer

According to question,we have John's position = 16th from the left Johnson's position = 8th from the right After interchanging their positions , John's position = 33rd from left ∴ Total number of students = John's position + Johnson's position - 1 Total number of students = 33 + 8 – 1 = 40

Question 8

At a college party 5 girls are sitting in a row. P is to the left of M and to the right of O. R is sitting to the right of N, but to the left of O. Who is sitting in the middle?

Accepted Answer

According to question, We can draw a figure , in which P is to the left of M and to the right of O. R is sitting to the right of N, but to the left of O. From given figure it is clear that , O is sitting in the middle. Sitting arrangement :-

Question 9

Five children are standing in a row. O is third from M who is standing left of N, and P is on the left of Q who is fourth from N. What is the position of P from right?

Accepted Answer

According to question,O is third from M who is standing left of N, and P is on the left of Q who is fourth from N. As shown in figure , the position of P from right is Second . Sitting arrangement :-

Question 10

Row of 15 children – position shift reasoning: Raju is shifted three places towards the right and then becomes 8th from the right end. What was Raju’s original position from the left end of the row (before the shift)?

Accepted Answer

Introduction / Context:This is a classic ranks-and-positions puzzle. We know the total number of children and how Raju’s rank changes after moving three places to the right. We must recover his original (pre-shift) position from the left end.Given Data / Assumptions:Total children N = 15.After shifting 3 places to the right, Raju becomes 8th from the right.We assume a single straight row numbered 1…15 from left to right.Concept / Approach:Convert a right-end rank to a left-end rank using left_rank = N − right_rank + 1. Then undo the “shift right by 3” to retrieve the original left-end rank.Step-by-Step Solution:After shift, right-rank(Raju) = 8 ⇒ left-rank(after) = 15 − 8 + 1 = 8.A shift 3 to the right increases his left-rank by +3.So original left-rank(before) = 8 − 3 = 5.Verification / Alternative check:Place a simple index to confirm: if before he was at left position 5, moving three to the right lands him at position 8 from left; in a row of 15, that is indeed 8th from right (15 − 8 + 1 = 8).Why Other Options Are Wrong:Values like 12 or 14 contradict the derived conversion; 6 would imply an after-shift left rank of 9, not matching the given 8th from right.Common Pitfalls:Forgetting the +1 when converting between right-rank and left-rank; or subtracting rather than adding the shift when moving right.Final Answer:5

Question 11

Row in East–West direction – swap positions and count total: Dipika is 11th from the West. Sudesh is 15th from the East. After exchanging positions, Sudesh becomes 9th from the East. How many persons are in the row?

Accepted Answer

Introduction / Context:When two people swap seats, each takes the other’s rank. Using this fact with left/right conversions yields the total number of persons in the row.Given Data / Assumptions:Dipika = 11th from West.Sudesh = 15th from East (before swap).After swap, Sudesh is 9th from East.Concept / Approach:After exchanging positions, Sudesh acquires Dipika’s original seat. Let N be total persons. The left-rank of Dipika’s seat is 11; the equivalent right-rank is N − 11 + 1 = N − 10. This must equal Sudesh’s new right-rank 9.Step-by-Step Solution:Set N − 10 = 9 ⇒ N = 19.Verification / Alternative check:With N = 19, the position 11 from West corresponds to 9 from East (19 − 11 + 1 = 9), matching the given post-swap status of Sudesh.Why Other Options Are Wrong:All other totals produce a different right-rank than 9 after the swap.Common Pitfalls:Missing the +1 in conversions or mistakenly swapping the wrong ranks.Final Answer:19

Question 12

Five friends facing North – who is at the extreme right end? Constraints: Ankit sits immediately to the right of Anjum. Amit is to the left of Priya and immediately to the right of Ram (so Ram–Amit are adjacent). Ram is somewhere to the right of Ank…

Accepted Answer

Introduction / Context:All friends face North, so “left” and “right” are read in the normal left-to-right order. We must determine who occupies the extreme right seat.Given Data / Assumptions:Ankit is immediately to the right of Anjum ⇒ (Anjum, Ankit) adjacent with Ankit on the right.Ram and Amit are adjacent with Amit immediately to the right of Ram ⇒ (Ram, Amit).Amit is to the left of Priya ⇒ Priya lies to the right of Amit.Ram is to the right of Ankit.Concept / Approach:Place the adjacencies first, then satisfy the “to the right of” conditions. Use a 5-seat template and try feasible placements without breaking adjacency.Step-by-Step Solution:Try: 1 Anjum, 2 Ankit (satisfies immediate-right).Ram must be to the right of Ankit. Place 3 Ram, 4 Amit (adjacent pair).Priya must be to the right of Amit ⇒ Priya at 5.Arrangement: 1 Anjum, 2 Ankit, 3 Ram, 4 Amit, 5 Priya.Verification / Alternative check:All constraints hold, and the extreme right end is seat 5, occupied by Priya.Why Other Options Are Wrong:They are not at seat 5 in any arrangement satisfying all constraints simultaneously.Common Pitfalls:Breaking adjacency when moving Ram relative to Ankit or placing Priya to the left of Amit.Final Answer:Priya

Question 13

Five friends on a bench – identify the two extremes: Rules: C is to the left of A, and A is to the left of B (C … A … B). Also, D is to the right of B and to the left of E (B … D … E). Who are at the two extreme ends (leftmost and rightmost)?

Accepted Answer

Introduction / Context:We are given two chains that must be merged into a single left-to-right order. The task is to identify the extreme-left and extreme-right persons.Given Data / Assumptions:C … A … B (A is to the left of B but to the right of C).B … D … E (D is to the right of B but to the left of E).Distinct persons A, B, C, D, E sit in one row from left to right.Concept / Approach:Merge the two constraints by overlapping the shared person B and preserving order on each side. The combined consistent sequence becomes C – A – B – D – E.Step-by-Step Solution:Start with C – A – B from the first rule.Append D to the right of B and E to the right of D to satisfy the second rule.The final arrangement is C (leftmost), A, B, D, E (rightmost).Verification / Alternative check:Any reordering that changes the relative positions (e.g., placing D left of B or A right of B) will violate at least one rule.Why Other Options Are Wrong:Pairs that do not include C on the far left or E on the far right contradict the merged chain.Common Pitfalls:Misreading “left of” and “right of” or trying to place D to the left of B.Final Answer:C and E

Question 14

Seven members in a row – who sits exactly in the middle? Constraints (left-to-right ordering): C is left of B but right of D (D … C … B). A is right of B. F is right of E but left of D (E … F … D). H is left of E.

Accepted Answer

Introduction / Context:We have seven distinct members with multiple “to the left/right of” constraints. The goal is to determine who occupies the central (4th) position when everyone is arranged left to right.Given Data / Assumptions:D … C … B (C is between D and B, with C left of B).A is to the right of B ⇒ B … A.E … F … D (F is right of E but left of D).H is left of E ⇒ H … E.Concept / Approach:Chain the inequalities to form one consistent sequence. From E … F … D and H … E, we get H … E … F … D. From D … C … B and B … A, extend to the right: … D … C … B … A.Step-by-Step Solution:Concatenate: H – E – F – D – C – B – A.This satisfies all four constraints simultaneously.In a 7-seat order, the middle (4th) position is occupied by D.Verification / Alternative check:Any attempt to move D left of F breaks “F left of D”; moving C left of D breaks “D left of C”; placing A to the left of B breaks “A right of B.”Why Other Options Are Wrong:C, E, F are not at the 4th position in any arrangement that honors all constraints.Common Pitfalls:Not chaining all relations together and overlooking that the set H, E, F, D must precede C, B, A in that order.Final Answer:D

Question 15

Five boys in a row – who stands in the middle? Rules: C stands at the extreme right. D is to the right of E. B is to the left of E but to the right of A (A … B … E). Determine the boy in the exact middle position.

Accepted Answer

Introduction / Context:This is a 5-seat single-row ordering problem with an extreme fixed (C at far right) and two relational constraints. We must identify the central (3rd) seat occupant.Given Data / Assumptions:C is at the extreme right (seat 5).D is to the right of E ⇒ E … D.A … B … E (B is left of E but right of A).Concept / Approach:With C fixed at 5, fit A, B, E, D into seats 1–4 while respecting A < B < E and E < D. Only one linearization satisfies all constraints without conflict.Step-by-Step Solution:Place E at seat 3 and D at seat 4 to satisfy E … D and leave room for A and B to the left.Then A at seat 1 and B at seat 2 fulfill A … B … E.Final arrangement (left→right): 1 A, 2 B, 3 E, 4 D, 5 C.Therefore, the middle (seat 3) is E.Verification / Alternative check:Trying E at seat 4 would force D at 5, which conflicts with C fixed at 5. Any other placements violate either A … B … E or E … D.Why Other Options Are Wrong:A, B, C, D do not occupy the central seat in any valid arrangement.Common Pitfalls:Forgetting that “extreme right” is absolutely fixed, leaving too few slots for E and D.Final Answer:E

Question 16

Six friends A, B, C, D, E, and F are seated in a single row facing North. • C sits between A and E (immediately between them). • D is not at either end of the row. • B sits immediately to the right of E. • F is not at the rightmost end. • D sits exa…

Accepted Answer

Introduction / Context:Seating-arrangement questions test your ability to translate compact verbal constraints into a precise linear order. Here we have six friends (A, B, C, D, E, F) seated in a single row facing North. We must use all given conditions to pin down the unique arrangement and then report who sits immediately to the left of D. Because everyone faces North, “left” and “right” are interpreted from the point of view of the people, which matches our usual left-to-right diagram on paper.Given Data / Assumptions:Single row; all face North (so position index increases left to right).C is between A and E immediately (i.e., one of A/E – then C – then the other, consecutively).D is not at an end.B is immediately to the right of E (E, B are consecutive in that order).F is not at the right end.D is exactly third to the left of E (so D's position = E's position − 3).Concept / Approach:Convert the language into algebraic/positional relations. Use indexing 1..6 from left to right. Immediate-right/left constraints and fixed gaps (like “third to the left”) are especially powerful. Treat “C between A and E (immediately)” as a 3-block pattern A-C-E or E-C-A in consecutive positions. Combine with “E-B” consecutive order and “D = E − 3”. Eliminate placements that violate ends or contradictions.Step-by-Step Solution:1) Let positions be 1 2 3 4 5 6 (left → right). All face North, so this matches their left-to-right.2) From “D is third to the left of E”: position(D) = position(E) − 3. Therefore E cannot be at 1–3; valid E are {4,5,6} and D will be {1,2,3} respectively.3) “B is immediately to the right of E”: so (E, B) occupy consecutive positions (E at k, B at k+1). Hence E ≠ 6 (otherwise B would need position 7). So E ∈ {4,5} and then B ∈ {5,6}.4) “F is not at the right end”: so F ≠ 6. Keep this in mind for later pruning.5) “C is sitting between A and E (immediately)”: the only allowed consecutive triples are either A-C-E or E-C-A, in consecutive positions.6) Try E = 5 → then B = 6. With D = E − 3, D = 2. Since F is not at right end (6 is taken by B), F can be at {1,3,4}. Now place the triple A-C-E as consecutive. If we choose A-C-E occupying positions 3-4-5, that fits E = 5, so A = 3 and C = 4. Remaining person for position 1 is F. The full row becomes: (1) F, (2) D, (3) A, (4) C, (5) E, (6) B. All constraints check out: D not at end; E-B consecutive; F not at right end; D is exactly three left of E; and C indeed immediately between A and E.7) In this unique consistent arrangement, immediately to the left of D (which is at position 2) sits F (at position 1).Verification / Alternative check:Attempting E = 4 leads to conflicts with the required consecutive triple and the E-B block placement when all other constraints are enforced; the consistent completion found above satisfies every statement simultaneously. A quick re-scan confirms no rule is violated.Why Other Options Are Wrong:A: In the valid arrangement A is two seats to the right of D, not immediately left.E: E is three seats to the right of D (by rule), not immediately left.C: C sits to the right of D (two places away), not immediately left.None of these: Incorrect because F is a valid listed option and is indeed immediately left of D.Common Pitfalls:Misreading “between” as a non-consecutive positioning. Here it is immediate adjacency (A-C-E or E-C-A).Forgetting that everyone faces North; your left-to-right drawing already aligns with “left”/“right”.Overlooking the E-B consecutive order; this quickly restricts E's possible positions.Final Answer:F

Question 17

Six-member row arrangement: U is to the left of V but to the right of W; W is to the right of X; Y is to the right of Z; and Z is to the left of X. Who are the two members sitting exactly in the middle positions?

Accepted Answer

Introduction / Context:This seating-arrangement problem gives multiple left–right constraints for six members U, V, W, X, Y, Z seated in a single row. The goal is to determine the two people who occupy the middle two seats.Given Data / Assumptions:U is left of V but right of W.W is right of X.Y is right of Z.Z is left of X.Exactly six distinct people; exactly one per seat.Concept / Approach:Chain the inequalities to build a partial order. From X < W < U < V and Z < X plus Y > Z, assemble a consistent left-to-right lineup satisfying all relations, then read off the two middle positions.Step-by-Step Solution:From W right of X and U right of W and V right of U: X < W < U < V.Also Z left of X (Z < X) and Y right of Z (Z < Y).One valid order that fits all is: Z, Y, X, W, U, V.The middle seats (3rd and 4th) are X and W.Verification / Alternative check:Another valid order is Z, X, W, U, Y, V; but that violates “Y right of Z” if Y falls left of Z. The chosen order satisfies all four relations simultaneously.Why Other Options Are Wrong:ZY: these are at the left in our valid lineup, not the middle.UV or WV: positions (4,5) or (4,5) respectively, not the two center seats.None of these: incorrect because XW is attainable.Common Pitfalls:Forgetting that “left of” and “right of” are transitive and that Y only needs to be to the right of Z, not necessarily to the far right.Final Answer:XW

Question 18

Classroom with 5 rows: A, B, C, D, E are each in a different row, front (1st) to back (5th). A sits behind C but in front of B; C sits behind E; D sits in front of E. What is the order from the first row to the last?

Accepted Answer

Introduction / Context:This is a linear ordering problem across five rows, from front (first row) to back (last row). We must respect several “in front of / behind” constraints.Given Data / Assumptions:A is behind C but in front of B ⇒ C < A < B (where “<” means nearer the front).C is behind E ⇒ E < C.D is in front of E ⇒ D < E.All five are in distinct rows 1–5.Concept / Approach:Translate each phrase to an inequality chain from front (smaller index) to back (larger index) and then merge chains into a single total order.Step-by-Step Solution:From D < E and E < C we get D < E < C.From C < A < B we append to get D < E < C < A < B.Mapping to rows 1→5 yields: D (1st), E (2nd), C (3rd), A (4th), B (5th).Verification / Alternative check:Each original statement is satisfied by DECAB front to back.Why Other Options Are Wrong:They break at least one inequality (e.g., placing A ahead of C or D behind E).Common Pitfalls:Confusing “front” vs “back” ordering; we consistently treat “in front” as a smaller index.Final Answer:DECAB

Question 19

Five girls M, N, O, P, Q stand in a row. P is to the right of Q. N is to the left of Q but to the right of M. P is to the left of O. Who is at the extreme right end?

Accepted Answer

Introduction / Context:A straightforward single-row ordering with relative left–right statements. We need the person on the extreme right end.Given Data / Assumptions:P is right of Q.N is left of Q but right of M ⇒ M < N < Q.P is left of O ⇒ P < O.Concept / Approach:Combine partial orders: from M < N < Q and Q < P? No—actually P is right of Q ⇒ Q < P; then P < O gives full chain M < N < Q < P < O.Step-by-Step Solution:Arrange left→right: M, N, Q, P, O.The rightmost is O.Verification / Alternative check:All three statements are satisfied by the lineup above.Why Other Options Are Wrong:Any choice other than O contradicts the established chain.Common Pitfalls:Accidentally reversing the “left of”/“right of” inequalities.Final Answer:O

Question 20

Five students K, L, P, Q, S are in one row. S is to the right of L. P is to the left of L but to the right of K. S is to the left of Q. Who is first from the left end?

Accepted Answer

Introduction / Context:We must determine the leftmost student using relative left–right constraints.Given Data / Assumptions:P left of L but right of K ⇒ K < P < L.S right of L ⇒ L < S.S left of Q ⇒ S < Q.Concept / Approach:Combine to get the chain K < P < L < S < Q, which fixes the full order.Step-by-Step Solution:Left→right: K, P, L, S, Q.First from the left is K.Verification / Alternative check:Every original relation matches the obtained sequence.Why Other Options Are Wrong:L/P/S cannot be left of K under the given constraints.Common Pitfalls:Misplacing Q relative to S.Final Answer:K

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