2-bit vector operation (recovered intent = addition): Given 2-bit unsigned vectors [A] = 10 and [B] = 01 (A is MSB), compute [A] + [B].

Introduction / Context:
The original stem omitted the operator; by Recovery-First we adopt the standard teaching example aligned with nearby items: 2-bit vector addition. Treat [A]=10 (binary 2) and [B]=01 (binary 1) as unsigned and add them.

Given Data / Assumptions:

• Vectors are 2 bits wide, A is MSB.
• Unsigned addition; no saturation.
• Result reported as a 2-bit vector (no overflow here).

Concept / Approach:
2 + 1 = 3. In binary, 3 is 11, which fits in 2 bits; no extra carry beyond the 2-bit width is generated.

Step-by-Step Solution:

Verification / Alternative check:
Decimal check: 2 + 1 = 3 → binary 11.

Why Other Options Are Wrong:

Common Pitfalls:
Misreading the MSB/LSB order.

Final Answer:
[11]