Difficulty: Easy
Correct Answer: six
Explanation:
Introduction / Context:Digital subtractors typically reuse adder hardware by representing subtraction A − B as A + 2's-complement(B). This technique works for any word size and unifies the implementation of add and subtract.
Given Data / Assumptions:
Concept / Approach:Form the 2's-complement of the subtrahend (6) and add it to the minuend (9). Equivalently, invert the bits of 6 and add 1, then add to 9, propagating carries as usual.
Step-by-Step Solution:
Identify minuend A = 9 and subtrahend B = 6.Compute B_tc = two's-complement(B) = (~B) + 1.Add: A + B_tc; ignore end carry in fixed-width arithmetic.Verification / Alternative check:Numerically, 9 + (−6) = 3, matching the intended subtraction.
Why Other Options Are Wrong:
Multiplier/two/result/nine: Not the subtrahend; subtraction requires complementing B, not A.Common Pitfalls:Confusing one's-complement (~B) with two's-complement (~B + 1).
Final Answer:six
Discussion & Comments