TTL 7400 NAND gate output when HIGH: What is the proper name for the output current capability in the HIGH state for a single 7400 output pin?
-
Asource current
-
Bsink current
-
CIOH
-
Dsource current or IOH
Answer
Correct Answer: source current or IOH
Explanation
Introduction / Context:Logic datasheets specify separate output-current capabilities for LOW and HIGH states. Correct terminology matters when reading and applying VOH/VOL and fan-out specifications for TTL and CMOS outputs.
Given Data / Assumptions:
- Device: 7400-series TTL NAND gate.
- State of interest: output logic HIGH.
- Industry-standard notation: IOH for HIGH-state output current, IOL for LOW-state output current.
Concept / Approach:When a TTL output is HIGH, any external load connected to the pin draws current from the output to ground; the gate is “sourcing” current. The maximum guaranteed current in that state is specified as IOH (often a small magnitude compared with IOL). Conversely, in the LOW state the output “sinks” current, specified as IOL.
Step-by-Step Solution:
Identify state: output HIGH.Define direction: current leaves the output into the load — sourcing.Use correct symbol: IOH denotes HIGH-state output current capability.Verification / Alternative check:Datasheets list IOH and IOL separately (e.g., IOH ≈ -0.4 mA, IOL ≈ 16 mA for LS-TTL), confirming the naming convention and asymmetry.
Why Other Options Are Wrong:
- “Sink current” applies to the LOW state.
- “source current” alone is descriptive but omits the standard symbol; “IOH” alone omits the verbal description. The most complete, unambiguous phrasing is “source current or IOH.”
Common Pitfalls:Confusing sourcing with sinking directions; misreading the sign convention for IOH (often negative to indicate current leaving the device).
Final Answer:source current or IOH.