Difficulty: Easy
Correct Answer: sink, source current
Explanation:
Introduction / Context:Open-collector outputs are ubiquitous for wired-OR logic, level shifting, and driving external loads like LEDs or relays (through appropriate interfaces). Knowing whether they can sink or source current determines how you connect pull-ups and loads.
Given Data / Assumptions:
Concept / Approach:Because the internal device only provides a path to ground, it cannot source current up to the node. It can only sink current. A pull-up resistor (or active pull-up) provides the current for the HIGH state; the transistor shunts it to ground for the LOW state. Thus, the correct phrasing is that an open-collector can sink current but cannot source current.
Step-by-Step Solution:
Turn transistor ON: current flows from VCC through pull-up and load into the collector to ground → sinking action.Turn transistor OFF: node floats and is pulled up by the resistor → output becomes HIGH.No sourcing path from inside the chip to raise the node by itself.Therefore, capability = sink current; limitation = cannot source current.Verification / Alternative check:Datasheets specify I_OL (sink) but not I_OH sourcing in open-collector mode; application circuits always include a pull-up resistor.
Why Other Options Are Wrong:
Source, sink current: implies internal sourcing path, which does not exist.“Source/sink voltage”: voltage is not “sourced” in this context; current capability is the correct descriptor.Common Pitfalls:Omitting the pull-up resistor and concluding the output is stuck LOW or undefined; forgetting level shifting limits of the pull-up voltage vs. device ratings.
Final Answer:sink, source current
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