Difficulty: Easy
Correct Answer: source 400 µA of current to no more than 10 attached gates
Explanation:
Introduction / Context:TTL (Transistor-Transistor Logic) families specify distinct source/sink capabilities depending on whether an output is HIGH or LOW. Designers must respect these limits to maintain valid logic levels and avoid overloading. The question focuses on the HIGH-state capability and the conventional fanout interpretation.
Given Data / Assumptions:
Concept / Approach:At logic HIGH, the TTL output can source only a small current (hundreds of microamps). Dividing the available source current by the required HIGH input current per load gives a loading limit of roughly 10 standard TTL inputs.
Step-by-Step Solution:
Identify HIGH-state drive: I_OH ≈ −0.4 mA (sources current).Identify receiver requirement: I_IH ≈ 40 µA per input.Compute fanout: 0.4 mA / 40 µA ≈ 10 inputs.State the capability: sources about 400 µA total to no more than ~10 standard loads.Verification / Alternative check:Datasheets for 74xx TTL list these limits explicitly; TTL gates are stronger at sinking current in LOW state (16 mA) than sourcing at HIGH.
Why Other Options Are Wrong:
Sink 16 mA: this is LOW-state behavior, not HIGH-state.Source 16 mA: far exceeds HIGH-state source capability.Sink 400 µA: sign is reversed and not the defining HIGH-state spec.Common Pitfalls:Confusing source vs. sink directions; misapplying LOW-state numbers to the HIGH state; ignoring that different TTL subfamilies (LS, ALS, etc.) tweak values but preserve the general relationships.
Final Answer:source 400 µA of current to no more than 10 attached gates
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