Difficulty: Easy
Correct Answer: ID versus VGS
Explanation:
Introduction / Context:
For JFET biasing, the key device curve is the transfer (transconductance) characteristic, which shows how the control voltage VGS sets the drain current ID. Designers use it to select the Q-point and to estimate small-signal parameters.
Given Data / Assumptions:
Concept / Approach:
The JFET transfer characteristic plots ID as a function of VGS, often following a square-law-like relation between 0 and the pinch-off voltage VP. This is distinct from the output characteristic, which plots ID versus VDS at fixed VGS.
Step-by-Step Solution:
Hold VDS large enough for saturation.Sweep VGS and measure ID.Plot ID (vertical axis) versus VGS (horizontal axis) → transfer curve.
Verification / Alternative check:
Datasheets show both families: output characteristics (ID–VDS) and transfer characteristics (ID–VGS). The latter is used to derive gm as the slope dID/dVGS.
Why Other Options Are Wrong:
Options involving IC/VCE refer to BJTs, not JFETs.
IS versus VDS is not a standard JFET characterization.
ID × RDS is not a device characteristic axis pair.
Common Pitfalls:
Confusing the transfer curve with the output characteristic; they serve different purposes in design.
Final Answer:
ID versus VGS
Discussion & Comments