Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

We are given:

• Speed of Train A = 60 km/h
• Speed of Train B = 90 km/h
• Length of Train A = 1.10 km = 1100 m
• Length of Train B = 0.90 km = 900 m

Step 1: Find total distance to be coveredTotal length = 1100 + 900 = 2000 meters

Step 2: Find relative speedRelative Speed = 60 + 90 = 150 km/hConvert to m/s: 150 × (1000 / 3600) = 41.67 m/s

Step 3: Calculate time takenTime = Distance / Speed= 2000 / 41.67 = 48 seconds

Final Answer:The time taken by the slower train to cross the faster one is 48 seconds