Opposite directions; distance difference at meeting Two trains start simultaneously from Aligarh and Delhi toward each other at 16 km/h and 21 km/h. When they meet, one has traveled 60 km more than the other. What is the distance between the stations?

Introduction / Context:
For two objects moving toward each other, the distances each has covered at meeting are proportional to their speeds. If the faster covers 60 km more, the time until meeting can be deduced from the speed difference.

Given Data / Assumptions:

• Speeds: 16 km/h and 21 km/h.
• Difference in distances at meeting: 60 km (the faster train covers more).

Concept / Approach:
Let t be the time to meet. Distance difference = (21 − 16) * t = 5t = 60 ⇒ t = 12 h. Total distance = (16 + 21) * t.

Step-by-Step Solution:

Verification / Alternative check:
Individual distances: 16*12 = 192 km and 21*12 = 252 km; difference 60 km; sum 444 km.

Why Other Options Are Wrong:
440 and 445 are near misses; 450 ignores exact arithmetic.

Common Pitfalls:
Using the sum of speeds to compute the difference in distances; the difference uses (v2 − v1).

Final Answer:
444 km