Lathe capacity terminology — swing over bed The swing diameter over the bed of a lathe is how many times the centre height (centre above bed)?
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AEqual to the centre height
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BTwice the centre height
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CThree times the centre height
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DOne-half of the centre height
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EFour times the centre height
Answer
Correct Answer: Twice the centre height
Explanation
Introduction / Context:Lathe capacity is commonly specified by ‘‘swing over bed’’ and ‘‘distance between centres.’’ Understanding the geometric relationship between swing and centre height is essential for checking whether a workpiece diameter can clear the bed.
Given Data / Assumptions:
- Centre height H is the vertical distance from bed top to spindle centreline.
- Swing over bed is the maximum work diameter that can rotate without hitting the bed.
Concept / Approach:If the spindle centre is H above the bed, a circle of radius H can rotate without interference, so the maximum diameter equals 2H. Hence, swing over bed equals twice the centre height.
Step-by-Step Solution:Let centre height = H.Clearance radius = H ⇒ maximum diameter = 2H.Therefore, swing over bed = 2 × centre height.
Verification / Alternative check:Machine nameplates often list, e.g., ‘‘Swing over bed 400 mm’’ which implies centre height of 200 mm.
Why Other Options Are Wrong:Other multiples do not match the simple geometry of radius versus diameter; one-half would correspond to radius, not diameter.
Common Pitfalls:Confusing ‘‘swing over carriage’’ (smaller) with ‘‘swing over bed.’’ Accessories reduce practical swing further.
Final Answer:Twice the centre height