Difficulty: Easy
Correct Answer: Twice the centre height
Explanation:
Introduction / Context:
Lathe capacity is commonly specified by ‘‘swing over bed’’ and ‘‘distance between centres.’’ Understanding the geometric relationship between swing and centre height is essential for checking whether a workpiece diameter can clear the bed.
Given Data / Assumptions:
Concept / Approach:
If the spindle centre is H above the bed, a circle of radius H can rotate without interference, so the maximum diameter equals 2H. Hence, swing over bed equals twice the centre height.
Step-by-Step Solution:
Let centre height = H.Clearance radius = H ⇒ maximum diameter = 2H.Therefore, swing over bed = 2 × centre height.
Verification / Alternative check:
Machine nameplates often list, e.g., ‘‘Swing over bed 400 mm’’ which implies centre height of 200 mm.
Why Other Options Are Wrong:
Other multiples do not match the simple geometry of radius versus diameter; one-half would correspond to radius, not diameter.
Common Pitfalls:
Confusing ‘‘swing over carriage’’ (smaller) with ‘‘swing over bed.’’ Accessories reduce practical swing further.
Final Answer:
Twice the centre height
Discussion & Comments