Heat partition in cutting – continuous chip: In continuous chip machining (good ductility, sharp tool, adequate speed), which sink removes the largest fraction of generated heat? Assess the statement “the tool takes the maximum heat.”

Difficulty: Easy

Correct Answer: No

Explanation:


Introduction / Context:
Metal cutting converts mechanical work into heat at the primary shear zone and the tool–chip interface. Where that heat goes affects temperatures, tool wear, and part integrity. This question checks understanding of heat partition in continuous chip formation.



Given Data / Assumptions:

  • Ductile material, sharp tool, typical production speeds.
  • Continuous chip with or without a built-up edge.
  • Coolant may or may not be applied but does not change the basic partition trend.


Concept / Approach:
In continuous chip cutting, most heat is carried away by the flowing chip because it is in intimate contact with the hot shear zone and departs the cutting region quickly with a relatively high mass flow and temperature rise. The tool and work each receive smaller portions of the heat.



Step-by-Step Solution:

Consider energy balance: Q_total = Q_chip + Q_tool + Q_work.Experiments show Q_chip is the dominant term for many ductile alloys at moderate to high speeds.Therefore the assertion “tool takes the maximum heat” is false; the chip is the primary heat carrier.Tool temperature control still matters because even a smaller fraction can raise tool-tip temperature significantly.


Verification / Alternative check:
Thermocouple tools and inverse heat conduction models consistently attribute the largest share of heat to the chip stream in continuous chip cutting.



Why Other Options Are Wrong:
Conditional statements about specific tool materials or hardened steels are special cases; the general rule under continuous chip conditions remains that the chip removes the most heat.



Common Pitfalls:
Confusing local peak temperature at the tool tip with total heat fraction; peak temperature can be high even if the fraction of heat to the tool is smaller than to the chip.



Final Answer:
No

More Questions from Production Engineering

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion