Electromagnetic induction condition: Will a stationary conductor in a static (unchanging) magnetic field have a voltage induced across it?

Difficulty: Easy

Correct Answer: Incorrect

Explanation:


Introduction / Context:
Faraday’s law governs when and how an electromotive force (EMF) is induced. Understanding the required conditions—motion of the conductor, time-varying magnetic fields, or changing circuit area—is crucial in generator design, sensor placement, and EMI troubleshooting.


Given Data / Assumptions:

  • A straight conductor is stationary in space.
  • The magnetic field present is static (no change in magnitude or direction over time).
  • No change in loop area or orientation occurs.


Concept / Approach:
Faraday’s law in words: the induced EMF around a closed path equals the negative time rate of change of magnetic flux linking that path. If neither the field nor the geometry/orientation changes, the magnetic flux is constant and its time derivative is zero, so no EMF is induced. Motional EMF requires relative velocity between conductor and field (v × B). Transformer EMF requires dB/dt (time-varying field). Neither condition is met here.


Step-by-Step Solution:

Assess flux linkage: Φ is constant because B and geometry are constant.Compute rate of change: dΦ/dt = 0 → induced EMF e = 0.Check motional EMF: v = 0 for a stationary conductor → e_motional = B * L * v = 0.Conclude: no induced voltage under the stated conditions.


Verification / Alternative check:
Start moving the conductor, rotate it, or vary the magnetic field with time (e.g., AC excitation). A measurable EMF immediately appears, confirming the necessity of changing flux linkage.


Why Other Options Are Wrong:
Material choice (copper vs. others), extreme field strength, or temperature does not matter if dΦ/dt = 0 and v = 0; without change, no EMF is induced.


Common Pitfalls:
Assuming a strong static field alone causes EMF; forgetting that only a change in flux linkage—by motion or time-varying fields—creates induced voltage.


Final Answer:
Incorrect

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