Induction conditions: for a stationary conductor placed in a stationary (unchanging) magnetic field, what is the induced voltage across the conductor?

Difficulty: Easy

Correct Answer: equals 0 V

Explanation:


Introduction / Context:
Induced voltages require change—either motion relative to a magnetic field or a time-varying magnetic field. This question probes the special case where both the conductor and the magnetic field are stationary.



Given Data / Assumptions:

  • The conductor does not move (velocity v = 0).
  • The magnetic field is constant in time and space (dB/dt = 0).
  • No change in flux linkage with the conductor occurs.


Concept / Approach:
Faraday’s law indicates induced emf is related to the time rate of change of magnetic flux linkage. Motional emf requires nonzero velocity v across B (e = B * l * v). Transformer emf requires time-varying flux (e ∝ dΦ/dt). With both v = 0 and dΦ/dt = 0, there is no mechanism to produce an induced voltage, so the induced voltage is zero.



Step-by-Step Solution:

1) Check for motional induction: v = 0 → e_motional = B * l * v = 0.2) Check for transformer induction: dΦ/dt = 0 → e_transformer = dΦ/dt = 0.3) Sum of induced effects = 0.4) Therefore, the induced voltage is 0 V.


Verification / Alternative check:
An experiment with a stationary wire and a permanent magnet at rest shows no measurable emf; moving either the wire or the magnet produces a measurable voltage, confirming the need for change.



Why Other Options Are Wrong:
“Usually very large”: contradicts the requirement for motion or time variation.

“Varies with time”: no time variation exists in this setup.

“Depends on field strength”: field strength alone without motion or change does not induce a voltage across a stationary conductor.



Common Pitfalls:
Assuming a strong static magnet automatically induces emf; confusing static magnetic force effects with induction requirements.



Final Answer:
equals 0 V

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