Difficulty: Easy
Correct Answer: ω_n^2 / (s^2 + 2 ζ ω_n s + ω_n^2)
Explanation:
Introduction / Context:
Recognising the standard (canonical) transfer function of a second-order linear time-invariant (LTI) system is foundational for predicting overshoot, oscillations, settling time, and stability margins. The canonical form uses two interpretable parameters: the undamped natural frequency (ω_n) and the damping ratio (ζ). This question checks your ability to identify that exact standard expression among look-alike distractors that represent other dynamic elements or non-canonical forms.
Given Data / Assumptions:
Concept / Approach:
The canonical second-order transfer function is written as G(s) = ω_n^2 / (s^2 + 2 ζ ω_n s + ω_n^2). From this, step and frequency response features are read directly: underdamped (0 < ζ < 1), critically damped (ζ = 1), overdamped (ζ > 1). Any form that does not match this denominator pattern is not the standard second-order canonical expression, even if it is second-order or dynamic in some other way.
Step-by-Step Solution:
Verification / Alternative check:
Compare poles: the denominator s^2 + 2 ζ ω_n s + ω_n^2 produces complex poles at −ζ ω_n ± j ω_n sqrt(1 − ζ^2) for ζ < 1, consistent with classical second-order behaviour. Other presented forms do not enforce this pole pattern.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing “any second-order” with the “canonical second-order form.” The presence of a numerator zero changes transient characteristics and is not the template used to define ζ and ω_n.
Final Answer:
ω_n^2 / (s^2 + 2 ζ ω_n s + ω_n^2)
Discussion & Comments