Difficulty: Easy
Correct Answer: O2
Explanation:
Introduction / Context:Thermal-conductivity gas analyzers detect composition changes via heat transfer from a heated element to the surrounding gas. The signal depends on the thermal conductivity k of the gas mixture. Recognizing relative k values of typical flue gas components guides interpretation and instrument selection.Given Data / Assumptions:
Concept / Approach:At room temperature, approximate thermal conductivities are: CO2 ≈ very low (about 0.016 W/m·K), CO ≈ lower mid (≈ 0.024), N2 and O2 ≈ around air (≈ 0.026). Between N2 and O2, oxygen is slightly higher than nitrogen under common conditions. Therefore, among the listed flue gas species, O2 has the highest thermal conductivity and produces the largest conductive signal relative to the others.Step-by-Step Solution:
Rank k values: CO2 (lowest) < CO < N2 ≲ O2 (highest of the set).Relate analyzer signal magnitude to k differences.Select O2 as having the highest thermal conductivity.Verification / Alternative check:Property tables show air ≈ 0.026 W/m·K, O2 slightly above N2, validating the ranking for these species.
Why Other Options Are Wrong:
CO2: lowest k; often used as an example of poor thermal conductor among gases.N2: close to O2 but slightly lower.CO: lower than N2/O2; not the highest.Common Pitfalls:Assuming air’s k equals nitrogen exactly; O2’s slight increase matters when discriminating among listed gases.
Final Answer:O2
Discussion & Comments