Three runners A, B, and C run around a circular stadium and start together from the same point. Their lap times are A: 252 s, B: 308 s, and C: 198 s. After how much time will they all meet again at the starting point?

Difficulty: Medium

Correct Answer: 46 min and 12 s

Explanation:


Introduction:
This is the same common meeting concept as earlier lap problems. The time to meet again equals the least common multiple of their lap times because each runner must complete an integer number of laps by that moment.


Given Data / Assumptions:

  • A: 252 s per lap
  • B: 308 s per lap
  • C: 198 s per lap


Concept / Approach:
Compute LCM(252, 308, 198) and convert to minutes and seconds.


Step-by-Step Solution:

LCM = 2772 s 2772 s = 46 min and 12 s


Verification / Alternative check:
Each of 252, 308, and 198 divides 2772, so they are together again at that time. No smaller positive time works for all three.


Why Other Options Are Wrong:
The other values are not common multiples of all three lap times.


Common Pitfalls:
Forgetting to include the third runner when taking the LCM, which yields an incorrect earlier time.


Final Answer:
46 min and 12 s

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