Difficulty: Easy
Correct Answer: 9
Explanation:
Introduction:
To minimize the number of rows while keeping an equal number of trees per row for each variety, we choose the count per row as the highest common factor of the three totals. That makes each row as full as possible and reduces the number of rows.
Given Data / Assumptions:
Concept / Approach:
Trees per row = HCF(30, 45, 60). Number of rows = (30 + 45 + 60) / trees per row.
Step-by-Step Solution:
Verification / Alternative check:
Using any smaller common factor would result in fewer trees per row and more rows, so 15 per row is optimal for minimizing rows.
Why Other Options Are Wrong:
10, 12, 15, or 25 do not match the computed minimum number of rows from the correct common divisor approach.
Common Pitfalls:
Using the least common multiple or dividing each count differently, which violates the equal trees per row requirement.
Final Answer:
9
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