For any integer n, evaluate HCF(22n + 7, 33n + 10).

Difficulty: Easy

Correct Answer: 1

Explanation:


Introduction:
The HCF of linear expressions in n can often be simplified using the Euclidean algorithm by forming integer combinations that remove n, possibly yielding a constant HCF.


Given Data / Assumptions:

  • Expressions: 22n + 7 and 33n + 10
  • n is any integer


Concept / Approach:
Apply the Euclidean algorithm to reduce the pair step by step until reaching a constant. If that constant is 1, the HCF is 1 for all integers n.


Step-by-Step Solution:

(33n + 10) - (22n + 7) = 11n + 3 (22n + 7) - 2 * (11n + 3) = 1 Therefore, HCF(22n + 7, 33n + 10) = HCF(11n + 3, 1) = 1


Verification / Alternative check:
Since an integer combination of the two gives 1, they are coprime for all integer n.


Why Other Options Are Wrong:
0 is not a valid HCF here, 11 is not a universal divisor of both expressions for all n, and None of these does not apply because 1 is correct.


Common Pitfalls:
Stopping the Euclidean steps early and missing the reduction to 1.


Final Answer:
1

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