At Srinagar, starting at 9 a.m. on a certain day, snow began to fall at a rate of $1\frac{1}{4}$ inches every two hours until 3 p.m. If there was already $2\frac{1}{4}$ inches of snow on the ground at 9 a.m., how many inches of snow was on the ground at 3 p.m. that day?
Aptitude
Simplification
Difficulty: Easy
Choose an option
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A$3\frac{3}{4}$
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B6
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C7
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D$7\frac{1}{2}$
Answer
Correct Answer: 6
Explanation
### Concept & Logic
This problem involves calculating a total accumulation by multiplying a rate over a specific time interval and adding it to an initial baseline quantity.
### Step-by-Step Solution
* **Given:**
* Initial snow on the ground = $2\frac{1}{4} = 2.25$ inches.
* Rate of snowfall = $1\frac{1}{4} = 1.25$ inches per 2 hours.
* Time duration (from 9 a.m. to 3 p.m.) = 6 hours.
* **Calculation:**
First, determine the snowfall per hour:
$$\text{Hourly rate} = \frac{1.25}{2} = 0.625 \text{ inches/hour}$$
Next, calculate the total snow fallen during the 6-hour window:
$$\text{Total fall} = 6 \times 0.625 = 3.75 \text{ inches}$$
Finally, add this new accumulation to the initial amount on the ground:
$$\text{Total snow} = 2.25 + 3.75 = 6 \text{ inches}$$
### Exam Strategy & Shortcut
Since the rate is given per 2 hours, and 6 hours is exactly three 2-hour intervals, skip the per-hour calculation entirely. Simply multiply the interval rate by the number of intervals:
$3 \times 1\frac{1}{4} = 3\frac{3}{4}$ inches.
Add this directly to the initial baseline:
$2\frac{1}{4} + 3\frac{3}{4} = 6$ inches.
This mental math pathway avoids decimal conversions completely.
### Common Pitfall
Students often forget to add the initial snow amount ($2\frac{1}{4}$) to the accumulated snowfall, incorrectly choosing option (a) $3\frac{3}{4}$. Always reread the final question line to ensure all starting conditions are factored into the final answer.
### Final Answer
**Therefore, the correct answer is 6.**