The area of a square is 49 mm².\nWhat is the length of each side?

Q: The area of a square is 49 mm².\nWhat is the length of each side?

Introduction / Context: The side of a square equals the positive square root of its area. Given Data / Assumptions: A = 49 mm². Concept / Approach: Side s = √A. Step-by-Step Solution: s = √49 = 7 mm Final Answer: 7mm

Difficulty: Easy

5mm
6mm
7mm
8mm

Correct Answer: 7mm

Explanation:

Introduction / Context:
The side of a square equals the positive square root of its area.

Given Data / Assumptions:

A = 49 mm².

Concept / Approach:
Side s = √A.

Step-by-Step Solution:

s = √49 = 7 mm

Final Answer:
7mm

More Questions from Area

Find the area of the rectangle with length L = 5 inches and width W = 3 inches.
A wheelchair slalom has a rectangular course of length 30 m and breadth 16 m.\nFind the area of the course.
In trapezium ABCD with AB ∥ CD and AB < CD, suppose CD = 6 cm and the distance (height) between the parallel sides is 4 cm.\nIf area(ABCD) = 16 cm², find the length AB.
A circle has area 346.5 cm².\nFind its circumference (in centimetres).
Total surface area of a cube (side = 7.5 cm)\nFind the total surface area (in cm²) of a cube whose edge length is 7.5 cm.
Circle vs rectangle with perimeter 50 cm\nThe area of a circle equals the area of a rectangle whose perimeter is 50 cm and whose length exceeds its breadth by 3 cm. Find the diameter of the circle (in cm).
Square from its diagonal (14 cm)\nThe diagonal of a square is 14 cm. Compute the area of the square (in cm²).
Two externally touching circles\nTwo circles touch externally. The distance between their centres is 12 cm. If the radius of one circle is 7 cm, find the diameter (in cm) of the other circle.
Rhombus from area and one diagonal\nThe area of a rhombus is 84 cm² and one diagonal measures 7 cm. Find the length of the other diagonal (in cm).
Perimeter of a semicircle (radius = 28 cm)\nFind the perimeter of a semicircle of radius 28 cm (use perimeter = πr + 2r).

Discussion & Comments

No comments yet. Be the first to comment!