If 7 spiders weave 7 webs in 7 days (all working at the same constant rate), then how many days will 1 spider take to weave 1 web?

Difficulty: Easy

Correct Answer: 7

Explanation:


Introduction:
This problem encodes a constant-rate relation. The total output (webs) depends on the product of agents (spiders) and time (days), multiplied by each agent’s per-day rate. If 7 spiders produce 7 webs in 7 days, we can infer the unit rate per spider per day and scale it to one spider weaving one web.


Given Data / Assumptions:

  • 7 spiders → 7 webs in 7 days.
  • All spiders work independently at the same constant rate.
  • Find days for 1 spider to make 1 web.


Concept / Approach:
Let r be the number of webs produced by one spider in one day. Then total webs = spiders * days * r. Plug the given numbers to find r, then invert to get the time for one web by one spider.


Step-by-Step Solution:

Total webs = spiders * days * r 7 = 7 * 7 * r → r = 7 / 49 = 1/7 web per spider per day Time for 1 spider to make 1 web = 1 / r = 7 days


Verification / Alternative check:
If 1 spider takes 7 days per web, then 7 spiders in 7 days will produce 7 webs, matching the given scenario exactly.


Why Other Options Are Wrong:
1 day or 5 days would imply a much higher rate than stated; 8 days is too slow; “None” is unnecessary since 7 is precise and consistent.


Common Pitfalls:
Misreading “7 spiders 7 webs 7 days” as a trick to answer 1 day. Always compute the per-agent-per-day rate first.


Final Answer:
7

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