Slenderness ratio of a long column (structural mechanics): Among the following definitions, identify the correct engineering definition of “slenderness ratio” used in Euler/Rankine buckling design. It should express how long (L) a member is relative to its stiffness against bending (radius of gyration, k), and should clearly indicate that the least radius of gyration (k_min) is used for safety in buckling calculations.

Difficulty: Easy

Correct Answer: Length of column divided by least radius of gyration

Explanation:


Introduction / Context:
Columns fail primarily by buckling rather than crushing when they are thin and long. To quantify how “long and thin” a column is, engineers use the slenderness ratio. This ratio is central to Euler and Rankine formulas and guides whether elastic buckling or inelastic behavior governs design.


Given Data / Assumptions:

  • Column length considered between effective end conditions is L.
  • Radius of gyration about an axis is k = sqrt(I/A), where I is the second moment of area and A is the cross-sectional area.
  • Least radius of gyration k_min controls buckling since buckling occurs about the weakest (least stiff) axis.


Concept / Approach:

The slenderness ratio quantifies susceptibility to buckling and is defined as L/k. For safety we use the smallest k, hence L/k_min. Using k_min ensures we check buckling about the axis with minimum stiffness where buckling is most likely.


Step-by-Step Solution:

1) Identify k about principal axes: k_x and k_y.2) Determine k_min = min(k_x, k_y).3) Compute slenderness ratio: SR = L / k_min.4) Select the definition that matches SR = L / k_min.


Verification / Alternative check:

When k decreases (section more “slender” about that axis), L/k increases, which correctly predicts a greater tendency to buckle. This aligns with Euler's critical load proportional to 1/L^2 and inversely to k^2 via I = A k^2.


Why Other Options Are Wrong:

  • Area divided by k or least k is dimensionally inconsistent with a ratio used for buckling.
  • k divided by area has no direct buckling meaning.
  • Using “any axis” can miss the weakest axis; buckling checks must use k_min.


Common Pitfalls:

  • Using overall length instead of effective length that accounts for end conditions.
  • Checking only the strong axis and ignoring the weak axis (k_min).


Final Answer:

Length of column divided by least radius of gyration.

More Questions from Theory of Structures

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion