Difficulty: Easy
Correct Answer: 2
Explanation:
Introduction / Context:Load application rate strongly affects peak stresses in elastic members. Under impact or sudden loading, the bar stores more strain energy at the same final load level compared with a slowly applied (quasi-static) load. This concept is often introduced using energy methods in strength of materials.
Given Data / Assumptions:
Concept / Approach:
Use strain energy equivalence. Under gradual loading, the strain energy stored is (1/2) * W * δ, where δ is the static extension under W. Under sudden loading, the bar oscillates and its first peak force equals 2W, producing a peak stress twice the static stress for the same stiffness.
Step-by-Step Solution:
1) Static (gradual) case: σ_static = W / A. Energy = 0.5 * W * δ.2) Sudden case: initial energy input W * δ_static equals maximum strain energy at first peak: 0.5 * (2W) * δ_static.3) Therefore peak force = 2W and peak stress = 2 * (W/A) = 2 * σ_static.Verification / Alternative check:
From vibration solution of a single-degree-of-freedom system with step load, the displacement overshoots to 2δ_static at first peak, confirming a factor of 2 in stress.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
2.
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