Difficulty: Medium
Correct Answer: both (a) and (b)
Explanation:
Introduction / Context:
Machine shafts often experience simultaneous bending and torsion. Correct formulae for extreme normal and shear stresses at the outer fibre are essential for strength checks (e.g., maximum principal stress, maximum shear stress, or distortion-energy criteria).
Given Data / Assumptions:
Concept / Approach:
For a circular section: section modulus in bending Z = π * d^3 / 32, polar section modulus in torsion Zp = J / r = π * d^3 / 16. Hence, extreme bending stress and torsional shear stress follow directly by dividing the external actions by the corresponding moduli.
Step-by-Step Solution:
Verification / Alternative check:
Check limiting cases: with T = 0, only bending stress remains; with M = 0, only torsional shear remains. Dimensions are consistent (stress units for both expressions).
Why Other Options Are Wrong:
Common Pitfalls:
Using the wrong modulus (confusing Z with J or Zp), forgetting the factor 32 vs 16, or applying hollow-shaft formulae to solid shafts.
Final Answer:
both (a) and (b)
Discussion & Comments