Single-phase fully controlled bridge converter (R load) At what firing angles does a single-phase full converter (full-controlled bridge) produce its maximum average output voltage and its minimum (most negative) average output voltage?
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A0° and 180° respectively
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B180° and 0° respectively
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C0° and 90° respectively
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D90° and 0° respectively
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E45° and 135° respectively
Answer
Correct Answer: 0° and 180° respectively
Explanation
Introduction / Context:This question tests understanding of how the firing angle controls the average DC output of a single-phase fully controlled bridge (full converter) feeding a resistive load. Knowing the cosine control law is essential for rectifier design, motor control, and power supply engineering.
Given Data / Assumptions:
- Single-phase full-controlled bridge converter.
- Ideal thyristors and purely resistive load for clarity.
- Firing angle denoted by α (degrees).
Concept / Approach:
The average output voltage of a full converter is controlled by the firing angle as:
Vdc_avg = (2 * Vm / π) * cos(α)where Vm is the peak of the supply phase voltage. The cosine term directly sets sign and magnitude of the average DC output.
Step-by-Step Solution:
For α = 0° → cos(0°) = 1 → Vdc_avg = maximum positive = 2Vm/π.For α = 180° → cos(180°) = −1 → Vdc_avg = minimum (most negative) = −2Vm/π.Between these limits, Vdc_avg varies smoothly with cos(α).Verification / Alternative check:
Plotting Vdc_avg versus α shows a cosine curve with maximum at 0° and minimum at 180°. The sign reversal beyond 90° is consistent with inversion (power flow reversal) capability of a full converter.
Why Other Options Are Wrong:
180° and 0° reverses the true order. Pairs involving 90° or 45° do not correspond to extrema of the cosine function; 90° gives zero average, not an extremum.
Common Pitfalls:
Confusing the full converter with a half-controlled converter (which cannot produce negative average V). Also mixing up RMS and average values leads to wrong conclusions.
Final Answer:
0° and 180° respectively