Junction temperature calculation (SCR) A thyristor dissipates 40 W and operates in 20°C ambient. If the overall junction-to-ambient thermal resistance is 1.6°C/W, estimate the junction temperature (°C).

Difficulty: Easy

Correct Answer: 84° C

Explanation:


Introduction / Context:
Accurate junction temperature estimates are essential to ensure device reliability. The thermal resistance model provides a straightforward way to compute Tj from ambient temperature, power, and Rth,ja.


Given Data / Assumptions:

  • Ambient temperature Ta = 20°C.
  • Power dissipation P = 40 W.
  • Overall thermal resistance Rth,ja = 1.6°C/W.
  • Steady-state operation; linear thermal model applies.


Concept / Approach:

Temperature rise above ambient equals power times thermal resistance. Then junction temperature Tj = Ta + P * Rth,ja.


Step-by-Step Solution:

ΔT = P * Rth,ja = 40 * 1.6 = 64°CTj = Ta + ΔT = 20 + 64 = 84°C


Verification / Alternative check:

Confirm that Tj is below device maximum (commonly 110–125°C for many SCRs). At 84°C, the device is operating within typical safe limits.


Why Other Options Are Wrong:

  • 94°C or 114°C would imply larger Rth or power than given.
  • 164°C exceeds typical device limits and contradicts the calculation.


Common Pitfalls:

Omitting interface thermal resistances in practice can raise Tj. Measurement should be cross-checked with thermocouples or IR methods during prototyping.


Final Answer:

84° C

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