Junction temperature calculation (SCR) A thyristor dissipates 40 W and operates in 20°C ambient. If the overall junction-to-ambient thermal resistance is 1.6°C/W, estimate the junction temperature (°C).
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A114°C
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B164°C
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C94° C
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D84° C
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E—
Answer
Correct Answer: 84° C
Explanation
Introduction / Context:Accurate junction temperature estimates are essential to ensure device reliability. The thermal resistance model provides a straightforward way to compute Tj from ambient temperature, power, and Rth,ja.
Given Data / Assumptions:
- Ambient temperature Ta = 20°C.
- Power dissipation P = 40 W.
- Overall thermal resistance Rth,ja = 1.6°C/W.
- Steady-state operation; linear thermal model applies.
Concept / Approach:
Temperature rise above ambient equals power times thermal resistance. Then junction temperature Tj = Ta + P * Rth,ja.
Step-by-Step Solution:
ΔT = P * Rth,ja = 40 * 1.6 = 64°CTj = Ta + ΔT = 20 + 64 = 84°CVerification / Alternative check:
Confirm that Tj is below device maximum (commonly 110–125°C for many SCRs). At 84°C, the device is operating within typical safe limits.
Why Other Options Are Wrong:
- 94°C or 114°C would imply larger Rth or power than given.
- 164°C exceeds typical device limits and contradicts the calculation.
Common Pitfalls:
Omitting interface thermal resistances in practice can raise Tj. Measurement should be cross-checked with thermocouples or IR methods during prototyping.
Final Answer:
84° C