Difficulty: Easy
Correct Answer: 4/13
Explanation:
Introduction / Context:We need P(King ∪ Spade) from a standard deck. Use inclusion–exclusion to avoid double counting the king of spades.
Given Data / Assumptions:There are 4 kings total and 13 spades total; the king of spades is in both sets.
Concept / Approach:P(A ∪ B) = P(A) + P(B) − P(A ∩ B).
Step-by-Step Solution:
P(king) = 4/52P(spade) = 13/52P(king of spades) = 1/52P(either) = (4 + 13 − 1)/52 = 16/52 = 4/13Verification / Alternative check:Counting: favorable cards are 3 non-spade kings + 13 spades = 16 distinct cards.
Why Other Options Are Wrong:17/52 double-counts; 13/52 is spades only; 3/13 undercounts.
Common Pitfalls:Forgetting to subtract the overlap (king of spades).
Final Answer:4/13
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