Difficulty: Easy
Correct Answer: 0.30
Explanation:
Introduction / Context:Prime-counting over a small range is straightforward by enumeration or recalling standard lists up to 50. Probability equals (number of primes up to 50)/50 for uniform selection from 1–50.
Given Data / Assumptions:
Concept / Approach:
Step-by-Step Solution:
Primes ≤ 50: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47 (15 numbers)Probability = 15 / 50 = 3 / 10 = 0.30Verification / Alternative check:Cross-check by excluding composites and 1; the remaining count remains 15, a standard fact set for small prime tables.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:0.30
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