Queuing theory: Which distribution most commonly models service time for basic M/M/1-type systems?

Introduction / Context:In queuing models, assumptions about arrival and service processes determine tractability. The classic M/M/1 model assumes memoryless behavior for both arrivals and service.

Given Data / Assumptions:

• Basic single-server queue with Markovian arrivals and service.
• Arrivals follow Poisson process.
• Service times are independent and identically distributed.

Concept / Approach:Poisson arrivals imply exponentially distributed interarrival times. For the M/M/1, service times are also exponentially distributed (memoryless). Normal distribution is unsuitable because it can yield negative times; Erlang is used in M/Ek/1 variants but not the basic M/M/1.

Step-by-Step Solution:

Verification / Alternative check:Derivations of steady-state metrics (L, Lq, W, Wq) rely on the memoryless property of exponential service.

Why Other Options Are Wrong:Normal can be negative; Poisson describes counts, not service durations; Erlang is a generalisation but not the default “M”.

Common Pitfalls:Confusing Poisson (arrivals) with exponential (service time/interarrivals).

Final Answer:

Exponential law