Difficulty: Easy
Correct Answer: Accurate
Explanation:
Introduction / Context:This item reaffirms the behavior of a series RLC at resonance, emphasizing the equality of reactances and the resulting purely resistive impedance that dictates the current peak for a given source voltage.
Given Data / Assumptions:
Concept / Approach:At resonance, |Z| = R (minimum), so I = V/|Z| is largest. Although VL and VC can be large and cancel phasorially, they do not increase |Z| at resonance; instead, they produce internal voltage magnification characterized by Q, while the source sees a small resistive |Z|.
Step-by-Step Solution:
Impose XL = XC → Z = R.Compare current off-resonance: |Z| grows as |XL − XC| increases → current falls.Therefore, the maximum current occurs at the resonant frequency.Verification / Alternative check:Measure current while sweeping frequency; the plot yields a bell-shaped resonance curve with peak at f0 and −3 dB bandwidth linked to Q.
Why Other Options Are Wrong:
Requiring L = C numerically is irrelevant; resonance depends on ωL = 1/(ωC).Parallel resonance property is different (feed current minimum).Q affects sharpness of the peak, not whether a peak exists.Common Pitfalls:Confusing internal reactive voltages with source current; overlooking that the source only “sees” R at resonance.
Final Answer:Accurate
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