Coil Q at resonance — effect of series resistance: Does increasing a coil’s series resistance increase its quality factor Q at resonance?

Difficulty: Easy

Correct Answer: Incorrect — increasing resistance lowers Q

Explanation:


Introduction / Context:
The quality factor Q expresses how under-damped or selective a resonant circuit is. For a series RLC at resonance, Q relates the reactive energy exchange to real power dissipation. Coil resistance is a major contributor to series loss, so its effect on Q is fundamental to RF design and filters.


Given Data / Assumptions:

  • Series resonant circuit model with inductor series resistance R.
  • Sinusoidal steady state at resonant frequency f0.
  • Ideal L and C except for the noted resistance.


Concept / Approach:
For series resonance, Q = X_L / R at f0 (equivalently Q = ω0L / R). Increasing R in the denominator reduces Q. Lower Q widens the bandwidth (BW ≈ f0/Q) and reduces peak voltage magnification across L and C at resonance.


Step-by-Step Solution:

Start with Q = ω0L / R.Increase R → denominator increases → Q decreases.Result: broader bandwidth, lower selectivity, lower tank magnification.


Verification / Alternative check:
Network analyzer measurements show increased 3 dB bandwidth and lower peak response as series resistance rises. Simulation likewise confirms Q ∝ 1/R for fixed L, C at f0.


Why Other Options Are Wrong:

Claims that higher R raises Q contradict the formula.Frequency or ESR caveats do not reverse the basic series relation Q = X_L/R at resonance.


Common Pitfalls:
Mixing up series and parallel definitions of Q; overlooking that parallel-resonant “Rp” enters Q_p = Rp / X_L, a different configuration.


Final Answer:
Incorrect — increasing resistance lowers Q

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