Difficulty: Medium
Correct Answer: Incorrect — |Z| ≈ 3606 Ω, not 9684 Ω
Explanation:
Introduction / Context:Numerical checks prevent order-of-magnitude mistakes in AC design. Series RLC impedance magnitude combines resistance and net reactance vectorially, not arithmetically. This item asks you to confirm or refute a specific impedance claim using given R, X_L, and X_C values.
Given Data / Assumptions:
Concept / Approach:For series RLC, Z = R + j(X_L − X_C). The magnitude is |Z| = √(R^2 + (X_L − X_C)^2). Reactances must be netted before combining with R. Plug in values carefully and keep units consistent (ohms).
Step-by-Step Solution:
Compute net reactance: X = X_L − X_C = 7.5 kΩ − 5.5 kΩ = 2.0 kΩ.Form magnitude: |Z| = √(R^2 + X^2) = √((3.0 kΩ)^2 + (2.0 kΩ)^2).Square terms: 9.0 + 4.0 = 13.0 (in (kΩ)^2).Take square root: √13.0 ≈ 3.606 kΩ → |Z| ≈ 3606 Ω.Verification / Alternative check:Phasor diagram shows a modest inductive reactance remaining; the impedance should be a few kilohms, not almost 10 kΩ. A quick calculator or spreadsheet confirms 3.606 kΩ.
Why Other Options Are Wrong:
“Correct — 9684 Ω” is far off the computed value.“Only at resonance” is irrelevant; the given X_L and X_C are not equal.“Cannot be determined” is false; R, X_L, X_C suffice.“R much larger than reactances” contradicts the provided numbers.Common Pitfalls:Adding R and reactances directly; forgetting to difference X_L and X_C before forming the magnitude; dropping kilo- prefixes during arithmetic.
Final Answer:Incorrect — |Z| ≈ 3606 Ω, not 9684 Ω
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