Bearings — a line has reduced (quadrantal) bearing N 87° W. What is its whole circle bearing (WCB), measured clockwise from north (0°–360°)?

Difficulty: Easy

Correct Answer: 273°

Explanation:


Introduction / Context:
Survey lines may be expressed either as reduced (quadrantal) bearings like N θ E/W or S θ E/W, or as whole circle bearings (WCB) measured 0°–360° clockwise from true or magnetic north. Converting correctly between these systems is essential for plotting, computations, and using different instruments consistently.


Given Data / Assumptions:

  • Reduced bearing: N 87° W (i.e., 87° west of north).
  • WCB is measured clockwise from north.
  • Standard quadrant conventions apply.


Concept / Approach:
N 87° W lies in the northwest quadrant. From north (0°), rotating clockwise to the west side means passing through 360° back to just beyond it. The equivalent WCB is 360° − 87° = 273°. General rule: N θ W → WCB = 360° − θ; N θ E → θ; S θ E → 180° − θ; S θ W → 180° + θ.


Step-by-Step Solution:

Identify quadrant: N 87° W → NW.Compute WCB: 360° − 87° = 273°.State final bearing: 273°.


Verification / Alternative check:
Sketch axes and mark 0° at north; move clockwise nearly to west (270°) and add 3° more: 273°, which matches the conversion.


Why Other Options Are Wrong:

  • 87°: This would be N 87° E.
  • 93°: Lies in NE quadrant; wrong side.
  • 3°: Near north; not in NW quadrant.


Common Pitfalls:
Forgetting that N θ W and S θ E swap around 360° and 180° respectively; always visualize the quadrant.


Final Answer:
273°

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