Difficulty: Medium
Correct Answer: + 0.000909 m
Explanation:
Introduction / Context:A steel tape elongates when subjected to higher pull than its standardization tension. If not corrected, the measured distance will be underestimated, because each laid tape length is slightly longer than nominal. The pull correction quantifies this elastic extension using Hooke’s law.
Given Data / Assumptions:
Concept / Approach:Elastic extension ΔL under axial force follows ΔL = (ΔP * L) / (A * E), in consistent units. A positive ΔP means the tape is longer than standard, so the correction to the measured length is additive by +ΔL per tape length used.
Step-by-Step Solution:
Convert to consistent units: L = 3000 cm; A = 0.15 cm^2.Compute ΔL = (10 kg * 3000 cm) / (0.15 cm^2 * 2.2 × 10^6 kg/cm^2).Denominator = 0.15 * 2.2 × 10^6 = 330000; numerator = 30000.ΔL = 30000 / 330000 = 0.090909… cm = 0.00090909 m.Sign: + (tape lengthened) → add 0.000909 m to the measured distance per 30 m length.Verification / Alternative check:Sensitivity: If the pull were less than standard, the correction would be negative (tape shorter). Magnitude scales linearly with ΔP and L, and inversely with A and E.
Why Other Options Are Wrong:
Common Pitfalls:Unit mistakes between mm^2 and cm^2, and forgetting that correction is added when the tape is longer than standard.
Final Answer:+ 0.000909 m
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