Rectangle with breadth 75% of length:\nThe breadth is 75% of the length. If the rectangle’s perimeter is 1050 m, find its area (in sq. m).

Introduction / Context:
Similar to related problems, a perimeter and a fixed proportional relation between sides allow us to solve for each dimension and then compute area.

Given Data / Assumptions:

• B = 0.75L.
• Perimeter P = 1050 ⇒ 2(L + B) = 1050 ⇒ L + B = 525.

Concept / Approach:
Substitute B = 0.75L into L + B = 525 to solve for L, then compute B and multiply to get the area.

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