Average speed = 2ab/(a+b)
= (2 x 4 x 6)/(4 + 6)
= 48/10
= 4.8 km/h
Average speed of entire journey
= (39 + 39 + 39)/(39/26 + 39/39 +39/52)
= 3/(1/26 + 1/39 +1/52)
= 3/[(6 + 4 + 3)/156]
= 3 x 156/13 = 36 km/h
? 1 m/s = 18/5 km/h
? 31/3 m/s = 10/3 m/s = (10/3) x (18/5) km/h
= 12 km/h
We know that, speed = Distance / Time
? Required speed = 300/15 =20 km/h
Required speed = Distance/ Time
= 690/30
= 23 km/h
We know that, Speed = Distance / Time
? Required distance = Speed x Time
= 37 x 8 = 296 km
We know that, speed = Distance / Time
? Required Time = Distance / Speed = 400/20 = 20 h
Given, speed of bus = 72 km/h = 72 x 5/18 = 20 m/s
? Distance travelled in 5 s = 5 x 20 = 100 m
We know that for relative speed, the two speeds will be added, if the motions of the two objects are in opposite directions.
? Required speed = 10 + 6 = 16 km/h
We know that for relative speed, the subtraction of speeds takes place, if the motions of the two objects are in the same direction.
? Required relative speed = 9 - 5 = 4 km/h
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