Decimal Fraction problems
- 1. In a polling booth, total number of voters is 1575 out of which 0.4 part are male voters. If a candidate gets 0.4 part of female votes, then find how many votes did the candidate get?
Options- A. 945
- B. 756
- C. 378
- D. 630 Discuss
Correct Answer: 756
Explanation:
Number of male voters = 4/10 of 1575 = 4/10 x 1575 = 630
Number of female voters=1575 - 630 = 945
Now, total votes that candidate got = (6/10) x 630 + (4/10) x 945 = 378 + 378 = 756
- 2. In a village, (5/8)th of the population are adults,half of the adults are male,(4/5)th of adult females are illiterate. if 400 females are illiterate, then the population of the village is?
Options- A. 2000
- B. 1500
- C. 1800
- D. 1600 Discuss
Correct Answer: 1600
Explanation:
Let the population of village = N
Then, adult's population = 5N/8
and adult females = 1/2 x 5N/8 = 5N/16
? illiterate females = 4/5 of adult female population
? 400 = 4/5 x 5N/16
? N = (400 x 16)/4
? N = 1600
- 3. (1/4)th of number of boys and (3/8)th of number of girls participated in annual sport days in the school. What fractional part of total number of students participated?
Options- A. 32%
- B. 20%
- C. 36%
- D. data inadequate Discuss
Correct Answer: data inadequate
Explanation:
Total number of students participated = (B/4 + 3G/4)
? Required percentage= (B/4 + 3G/4) / (B+G) x 100%
Clearly, given data is inadequate.
- 4. A scooter before overhauling requires 2/3 h service time every 45 days,while after overhauling it requires 2/3 h service time every 60 days. what fraction of pre-overhauling service time is saved in the latter case?
Options- A. 4/3
- B. 1/3
- C. 3/4
- D. 1/4 Discuss
Correct Answer: 1/4
Explanation:
Time required for service before overhauling = 2/3h = 40 min in 45 days
and time required for service after overhualing =2/3h= 40 min in 60 days
Now,LCM of 45 and 60 = 180 days
time required for service before overhauling is 180 days = 40 x 4 = 160 min
and time required for service before overhauling is 180 days =40 x 3 = 120 min
? fraction of time saved = 160 - 120/160 =40/160 = 1/4
- 5. From a rope 30 m long, a person cuts off as many pieces as possible, each 3 1/ 4 m long. What fraction of the whole will be left?
Options- A. 1/40
- B. 3/4
- C. 8/13
- D. 7/13 Discuss
Correct Answer: 1/40
Explanation:
Length of each piece = 31/4 = 13/4 m
Maximum pieces that can be cut = 30/(13/4) = 9
? Rope left = 30 - 13/4 x 9 = 120 - 117/4 = 3/4 m
? Required fraction = 3/4/30 = 1/4
- 6. If 0. 3+ 0. 6 + 0. 7 + 0. 8 = x, then x is equal to?
Options- A. 23/10
- B. 22/3
- C. 2.35
- D. 53/10 Discuss
Correct Answer: 22/3
Explanation:
0.3+ 0.6 + 0.7 + 0.8 = x,
? x = 3/9 + 6/9 + 7/9 + 8/9 = 24/9 = 8/3 = 22/3
- 7. A boy on being asked 13/14 of a certain fraction had made the mistake of dividing the fraction by 14/13 and so got an answer that exceeded the correct answer by 3/65. The correct fraction is?
Options- A. 14/45
- B. 12/65
- C. 13/45
- D. 2/7 Discuss
Correct Answer: 13/45
Explanation:
Let the fraction be N.
Then, N / (13/14) - (13/14) x N = 3/65
? 14N/13 - 13N/14 = 3/65
? (196N - 169N)/182 = 3/65
? 27N/182 = 3/65
? N = (3 x 182) / (27 x 65) = 14/45
So, correct answer will be (13/14) x (14/45) = 13/45
- 8. A man left (1/7)th of his property to his daughter and the remaining to his sons to be equally divided among them. If the share of the each son be double than that of the daughter. Then, find the number of sons?
Options- A. 2
- B. 3
- C. 6
- D. 4 Discuss
Correct Answer: 3
Explanation:
Let the total property = N
Then, property of his daughter = P/7
? Remaining property = P - P/7 = 6P/7
Now, this property is divided among his sons, so that each son gets twice the property of his daughter.
Let number of sons be K.
Then, 6N/7 x K = 2N/7
? K = 3
- 9. A vessel, full of water, weighs 16.5 kg. When the vessel is (1/4)th full, it weight 5.25 kg. Then, weight of the empty vessel (in kg) is?
Options- A. 1.125
- B. 4.5
- C. 1.5
- D. 3 Discuss
Correct Answer: 1.5
Explanation:
Let the weight of vesel = x kg
Then, 1/4 of volume of water = (5.25 - x)kg
Full volume of water = (16.5 - x)
? 4(5.25 - x) = (16.5 - x)
? 21 - 4x = 16.5 - x
? 21 - 16.5 = 3x
? x = 4.5/3 = 1.5 kg
- 10. A has twice as much money as B. They play together and at the end of the first game B wins one-third of A's money from A, what fraction of the sum that B now has, must A win black in the second game, so that they may have exactly equal money?
Options- A. 1/3
- B. 1/5
- C. 1/4
- D. 1/10 Discuss
Correct Answer: 1/10
Explanation:
Let A has ? 200 at the starting of game, then B has ? 100 at the starting of game.
After the game, money left with A = 200 - 200/3 = ? 400/3
? Total money with B = 100 + 200/3 = ? 500/3
Let the fraction of money lost by B = N
Then, 500/3 - N x 500/3 = 400/3 + N x 500/3
? 500/3 - 400/3 = 500N/3 + 500N/3
? 100/3 = 1000N/3
? N = (100/3) x (3/1000) = 1/10
so, the fraction of money lost is 1/10.
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