Difficulty: Medium
Correct Answer: Only I and either II or III
Explanation:
Introduction / Context:We must place four subjects into the 8–9, 9–10, 10–11, and 11–12 slots and determine Chemistry’s time. This is a classic sequence/ordering data-sufficiency problem.
Given Data / Assumptions:
Concept / Approach:Check which combinations of statements uniquely fix Chemistry’s slot. The aim is sufficiency, not full timetable reconstruction.
Step-by-Step Solution:
Using Statement I alone: B at 8–9 and M at 9–10. Remaining slots (10–11, 11–12) are for C and P, but order unknown → insufficient.I + II: With P last (11–12), the only remaining slot for C is 10–11 → Chemistry at 10–11 is fixed → sufficient.I + III: If M is immediately followed by C, then C is 10–11 (right after M at 9–10) → sufficient even without II.II + III without I: P last; M immediately followed by C, but M could be 8–9 (then C is 9–10) or M 9–10 (C 10–11), etc. Multiple possibilities → insufficient.Verification / Alternative check:Both (I+II) and (I+III) yield C at 10–11. No contradiction occurs; hence the answer requires I and either II or III.
Why Other Options Are Wrong:
Common Pitfalls:Confusing 'immediately followed' with 'somewhere after' and overlooking that sufficiency is about uniqueness of Chemistry’s slot, not the entire schedule.
Final Answer:Only I and either II or III
Discussion & Comments