Direction sense — Point X is in which direction with respect to Y? Statements: I. Point Z is at equal distance from both X and Y. II. From X, walk 5 km east; turn right and walk 5 km; turn right again and walk 5 km to reach Y.

Difficulty: Medium

Correct Answer: Statement II alone is sufficient; Statement I alone is not sufficient.

Explanation:

Introduction / Context:Find the relative direction of X from Y using movement instructions.

Given Data / Assumptions:

  • I: Z is equidistant from X and Y (a locus statement; says nothing about bearing).
  • II: Path from X → (E 5) → right (S 5) → right (W 5) = Y.

Concept / Approach:Resolve net displacement from X to Y using vector addition.

Step-by-Step Solution:

From II: Starting at X=(0,0): go to (5,0); right → south to (5,-5); right → west to (0,-5). Thus Y=(0,-5).Therefore, from Y to X is north by 5 km; equivalently, X is north of Y.Statement I alone defines a perpendicular bisector set; direction cannot be inferred.

Verification / Alternative check:Sketching confirms a down-and-back Γ path ending directly south of start.

Why Other Options Are Wrong:

  • I alone: infinite possibilities; no direction.
  • Either alone / Both together not sufficient / Both together sufficient: incorrect because II alone already yields a unique direction.

Common Pitfalls:Mistaking 'right' turn orientation; forgetting that right after heading east points south.

Final Answer:Statement II alone is sufficient; Statement I alone is not sufficient. (X is north of Y.)

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